JavaScript怎样无限遍历数组答:var arr = [12,23,34,[234,344,34],23,'你好',[123,34],12];var result = [];function isArray(obj) { return Object.prototype.toString.call(obj) === '[object Array]'; }function test(source) { for(var i = 0,len = source.length; i < len; i++) { var...
C#的,求一维数组中各元素的偶数之和。答:步骤:一、循环遍历数组中每一个元素 二、判断是否为偶数,若是,则相加 代码:int i = 0;int [] array = {1,2,3,4,5,6,7,8,9,10};int sum = 0;for(i = 0;i < array.Length;i ++){ if(array[i] % 2 ==0){ sum = sum + array[i];} } ...